To solve this problem it is necessary to apply the concepts related to the kinematic equations of motion.
By definition we know that speed can be expressed as
![v= (d)/(t)](https://img.qammunity.org/2020/formulas/physics/college/2zsqnpclznysqjppzrrg0gd8jhxwqoyppp.png)
Where,
t = time
d = distance
For this specific case we know that the speed traveled corresponds to the round trip, therefore
![v = (2d)/(t)](https://img.qammunity.org/2020/formulas/physics/college/ej6c7zk0h659hbmpjtg2jusnpcs9hxekc9.png)
Re-arrange to find t (The time taken to here the echo)
![t = (2d)/(v)](https://img.qammunity.org/2020/formulas/physics/college/si2twd91hri4idooylc8crd2fftfyy66ja.png)
Replacing with our values we have that the distance is equal to 65m
![t = (2*65)/(1530)](https://img.qammunity.org/2020/formulas/physics/college/abx3ev3ufp2degrd6gkzj9pzekzb70xorx.png)
![t = 0.085s](https://img.qammunity.org/2020/formulas/physics/college/w2e89ownkjm3elrx63z6szkfxbf23iqfhn.png)
Therefore the time before the dolphin hears the echoes of the clicks is 0.085s