Answer:
t=12.6 cm
Step-by-step explanation:
Given that
Q= 150 W
T₁ = −1.00ºC
T₂ = 37.0ºC
A= 2 m²
Lets take thermal conductivity of blubber
K= 0.25 W/(m.K)
Lets take thickness = t
We know that heat transfer due to conduction given as



t=0.126 m
t= 12.6 cm
Therefore thickness of the blubber is 12.6 m.