Answer:
t=12.6 cm
Step-by-step explanation:
Given that
Q= 150 W
T₁ = −1.00ºC
T₂ = 37.0ºC
A= 2 m²
Lets take thermal conductivity of blubber
K= 0.25 W/(m.K)
Lets take thickness = t
We know that heat transfer due to conduction given as
![Q=KA((T_2-T_1))/(t)](https://img.qammunity.org/2020/formulas/physics/college/og33pdy1w2avpq4teuahn0j2yu9s933e35.png)
![t=KA((T_2-T_1))/(Q)](https://img.qammunity.org/2020/formulas/physics/college/qo5i6y0i13qepaz1xro7d125jzrs5iou91.png)
![t=0.25* 2* ((37 + 1))/(150)](https://img.qammunity.org/2020/formulas/physics/college/jfw54j00f1ejlq5jcmml9h4tvlt88tw29i.png)
t=0.126 m
t= 12.6 cm
Therefore thickness of the blubber is 12.6 m.