Final answer:
The average force exerted by the bat during the collision is approximately 6238.33 N.
Step-by-step explanation:
To find the average force exerted by the bat during the collision, we can use the equation:
Faverage = Δp / Δt
where Faverage is the average force, Δp is the change in momentum, and Δt is the time of collision.
We are given the mass of the baseball and the change in velocity before and after the collision. The change in momentum is calculated as:
Δp = m * (vf - vi)
where m is the mass of the baseball, vf is the final velocity, and vi is the initial velocity.
Plugging in the given values, we have:
Δp = (0.145 kg) * (90 m/s - (-44 m/s))
Calculating this, we get:
Δp = 18.715 kg·m/s
Next, we need to convert the time of collision from milliseconds to seconds:
Δt = 3 ms = 0.003 s
Finally, we can calculate the average force:
Faverage = Δp / Δt = (18.715 kg·m/s) / (0.003 s)
Calculating this, we get:
Faverage ≈ 6238.33 N
Therefore, the average force exerted by the bat during the collision is approximately 6238.33 N.