Question

PLEASE HELP ME FRIENDS.​

Answer 1

πr`2+πr2=π(r`2+r2)

=π((r`+r)^2-2r`r)

58π=π((10)^2-2r`r)

58=100-2r`r

2r`r=42

r`r=21

r`=21/r

we know that: r`+r=10

21/r+r=10

(21+r^2)/r=10

21+r^2-10r=0

factorizeing:r=3or7

so r`=21/r=7or 3