Question

What is the pressure of 0.540 mol of an ideal gas at 35,5 L and 223 K?

Use PV = nRT and R= 8.314 okPa
molok
0.715 kPa
2.45 kPa
28.2 kPa
62.7 kPa
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Answer 1

Answer:c

Step-by-step explanation:

Answer 2

P = 28.2 Kpa

Step-by-step explanation:

Given data:

Volume = 35.5 L

Temperature = 223 K

Number of moles = 0.540 mol

R = 8.314 Kpa. L/mol.K

Pressure = ?

Solution:

PV = nRT

P = nRT / V

P = 0.540 mol . 8.314 Kpa. L/mol.K .223 K / 35.5 L

P = 1001.2 Kpa . L /35.5 L

P = 28.2 Kpa