Question

A rock of mass m = 0.0450 kg is attached to one end of a string and is whirled around in a horizontal circle. If the radius of the circle is 0.580 m and the angular speed is 2.34 rad/s. What is the tension in the string?

Answer 1

Tension, T = 0.1429 N

Step-by-step explanation:

Given that,

Mass of the rock, m = 0.0450 kg

Radius of the circle, r = 0.580 m

Angular speed,
`\omega=2.34\ rad/s`

The tension in the string is balanced by the centripetal force acting on it. It is given by :

`T=(mv^2)/(r)`

Since,
`v=r\omega`

`T=(m(r\omega)^2)/(r)`

`T=(0.0450* (0.580* 2.34)^2)/(0.580)`

T = 0.1429 N

So, the tension in the string is 0.1429 N. Hence, this is the required solution.