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Water flows through a horizontal 60 mm diameter galvanized iron pipe at a rate of 0.02 m3/s. If the pressure drop is 135 kPa per 10 m of pipe, do you think this pipe is

a) a new pipe,
b) an old pipe with somewhat increased roughness due to aging or
c) a very old pipe that is partially clogged by deposits. Justify your answer.

User Sockmonk
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1 Answer

4 votes

Answer:

pipe is old one with increased roughness

Step-by-step explanation:

discharge is given as


V =(Q)/(A) = ( 0.02)/(\pi \4 * (60* 10^(-3))^2)

V = 7.07 m/s

from bernou;ii's theorem we have


(p_1)/(\gamma)  +(V_1^2)/(2g) + z_1 = (p_2)/(\gamma)  +(V_2^2)/(2g) + z_2 + h_l

as we know pipe is horizontal and with constant velocity so we have


(P_1)/(\gamma ) + \frac{P_2 {\gamma } + (flv^2)/(2gD)


P_1 -P_2 = (flv^2)/(2gD) * \gamma


135 * 10^3 = (f * 10* 7.07^2)/(2* 9.81 * 60 * 10^(-5)) * 1000 * 9.81

solving for friction factor f

f = 0.0324

fro galvanized iron pipe we have
\epsilon  = 0.15 mm


(\epsilon)/(d) = (0.15)/(60) = 0.0025

reynold number is


Re =(Vd)/(\\u) = (7.07 * 60* 10^(-3))/(1.12* 10^(-6))

Re = 378750

from moody chart


For Re = 378750 and (\epsilon)/(d) = 0.0025


f_(new) = 0.025

therefore new friction factor is less than old friction factoer hence pipe is not new one

now for Re = 378750 and f = 0.0324

from moody chart

we have
(\epsilon)/(d) =0.006


\epsilon = 0.006 * 60


\epsilon = 0.36 mm

thus pipe is old one with increased roughness

User Leeb
by
8.5k points