Question

If a system has 2.00 × 10 2 kcal 2.00×102 kcal of work done to it, and releases 5.00 × 10 2 kJ 5.00×102 kJ of heat into its surroundings, what is the change in internal energy of the system?

Answer 1

336.8 kilo Joules is the change in internal energy of the system.

Step-by-step explanation:

The equation for first law of thermodynamics follows:

`\Delta U=Q+W`

where,

Q = heat added to the system

ΔU = Change in internal energy

W = work done

We have :

Amount of heat given out by the system will be negatuive as heat relased by the system = Q

Q=
`-5.00* 10^2 kJ`

Work done on the system will positive as work is done on the system:

w =
`2.00* 10^2 kCal=836.8 kJ`

`\Delta U=-5.00* 10^2 kJ+836.8 kJ=336.8 kJ`

336.8 kilo Joules is the change in internal energy of the system.