Answer:
10 ft x 10 ft
Area = 100 ft^2
Explanation:
Let 'S' be the length of the southern boundary fence and 'W' the length of the eastern and western sides of the fence.
The total area is given by:
![A=S*W](https://img.qammunity.org/2020/formulas/mathematics/college/swiesve2g1lj378joqzmb3wfnuk2crnmw3.png)
The cost function is given by:
![\$ 120 = \$3*2W+\$6*S\\20 = W+S\\W = 20-S](https://img.qammunity.org/2020/formulas/mathematics/college/80zztrm0hurlilrnaicbhsmlmq7ur51oo0.png)
Replacing that relationship into the Area function and finding its derivate, we can find the value of 'S' for which the area is maximized when the derivate equals zero:
![A=S*(20-S)\\A=20S-S^2\\(dA)/(dS) = (d(20S-S^2))/(dS)\\0= 20-2S\\S=10](https://img.qammunity.org/2020/formulas/mathematics/college/5cvzwxfme3cutjx54k8rjv2wbxmdqlxqzg.png)
If S=10 then W =20 -10 = 10
Therefore, the largest area enclosed by the fence is:
![A=S*W\\A=10*10 = 100\ ft^2](https://img.qammunity.org/2020/formulas/mathematics/college/dulcrjtstmonexg2a6r4d0kjezqvev1oe9.png)