Question

Find the distance between the two points in simplest radical form.
(5,−9) and (−3,−1)

Answer 1

8√2

Explanation:

delta math gave me the right answer after I got it wrong

Answer 2

The distance between the points ( 5 , - 9 ) and ( - 3 , - 1 ) is 4
`√(8)`

Explanation:

Given points as :

Point A = ( 5 , - 9 )

I.e (x_1 , y_1) = ( 5 , - 9 )

Point B = ( - 3 , - 1 )

I.e( x_2 , y_2) = ( - 3 , - 1 )

Let The distance between points A and B = AB

So From distance formula

Distance AB =
`\sqrt{(y_2 - y_1)^(2) + (x_2 - x_1)^(2)}`

So, Distance AB =
`\sqrt{( - 1 + 9)^(2) + ( - 3 - 5)^(2)}`

Or, Distance AB =
`\sqrt{(8)^(2) + (- 8)^(2)}`

Or, Distance AB =
`√(64 + 64)`

Or, Distance AB =
`√(128)`

∴ Distance AB = 4
`√(8)`

Hence The distance between the points ( 5 , - 9 ) and ( - 3 , - 1 ) is 4
`√(8)` Answer