Answer:
The ball will get upto the height of 3.26 meters.
Step-by-step explanation:
Initial velocity of the ball = u = 8 m/s
final velocity of the ball = v = 0 m/s ( upward)
Acceleration due to gravity ,a= -g =
![-9.8 m/s^2](https://img.qammunity.org/2020/formulas/physics/middle-school/8ubv6x12t0va47279kh53retr3139907te.png)
Height of the ball when kicked = s
Using third equation of motion :
![v^2-u^2=2as](https://img.qammunity.org/2020/formulas/physics/middle-school/kzr98dbu2wfj2ipzjwf8lasb185fsfra2y.png)
![(0 m/s)^2-(8 m/s)^2=2* (-g)* s](https://img.qammunity.org/2020/formulas/physics/middle-school/s5mdz11de6yc8p8xqlmi3clxtsxfxcymcg.png)
![(0 m/s)^2-(8 m/s)^2=2* (-9.8)* s](https://img.qammunity.org/2020/formulas/physics/middle-school/x4islquvjx73zlbv34e59mzv3effcpjyso.png)
![s=((-8 m/s)^2)/(2* -9.8 m/s^2)=3.26 m](https://img.qammunity.org/2020/formulas/physics/middle-school/fcgooba1w5jxs7n2cea26epeccnecnv9ud.png)
The ball will get upto the height of 3.26 meters.