11 pounds of apples for $40.59 Equation: t = $3.69n. 12 gallons of gasoline for $44.16 Equation: t = $3.68n. 15 magazines for $54.75 Equation: t = $3.65n. 14 sandwiches for $50.68 Equation: t = $3.62n with arrowBoth.
To match the proportional relationships to their corresponding equations:
1. 11 pounds of apples for $40.59
- The cost per pound is
![\( (40.59)/(11) \approx 3.69 \).](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4lbhf82th5uituh2heegb0oykibb89fz5c.png)
- Equation: t = $3.69n
2. 12 gallons of gasoline for $44.16
- The cost per gallon is
![\( (44.16)/(12) \approx 3.68 \).](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ellj9xfqp1o9zfz1lam4ji9d2xj6w4hkm2.png)
- Equation: t = $3.68n
3. 15 magazines for $54.75
- The cost per magazine is
![\( (54.75)/(15) \approx 3.65 \).](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ubkr6d9c2w7gcds7jij7tkgi3h3w5b43b7.png)
- Equation: t = $3.65n
4. 14 sandwiches for $50.68
- The cost per sandwich is
![\( (50.68)/(14) \approx 3.62 \).](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6g717isegg20mr2orf4jh9b3wsjjh7cff5.png)
- Equation: t = $3.62n
In each case, the equation t = kn represents the proportional relationship, where k is the constant unit rate of cost per item. The arrowBoth indicates the direction of the proportional relationship.