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R S and T are the vertices of one triangle E F and D are the vertices of another triangle m

User Hunterjrj
by
4.5k points

2 Answers

6 votes

Answer:

the answer is A. yes, by ASA; FD

Explanation:

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User Ceili
by
5.8k points
4 votes

Answer:

Complete question is attached with.

Both the triangles are congruent by ASA property of congruence and the segment RT is congruent to FD.

Explanation:

From angle sum property of the triangle we can find the measure of the missing angles.

As for
\triangle RST we can find
\angle T which is
180-(60+80)=40

And for
\triangle EFD we can find
\angle E which is
180-(60+40)=80

To find the congruence.

We see that
\angle S=80\ (deg) and
\angle E=80\ (deg)

Then
\angle R=60\ (deg) along with
\angle F=60\ (deg)

Between these two angles we have a segment that is equal in measure.

So two angles and a side in continuation, we can apply ASA property of congruence.

Now segment
RT and segemnt
FD are congruent as both the segment have equal measures on it.

So finally option A is the correct choice and both the triangles are congruent by ASA property.

And RT is congruent with FD.

R S and T are the vertices of one triangle E F and D are the vertices of another triangle-example-1
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