Answer:
8,345,925 lb-f
Step-by-step explanation:
We know pressure P = F/A = ρgh ⇒ F = ρghA = ρgV
F = ρgV where F = force, ρ = density of water = 1000 kg/m³ , g = acceleration due to gravity = 9.8 m/s² and V = 1 × 10⁶ gallons = 1 × 10⁶ gallons × 1m³/264.2 gallons = 3785 m³
So, F = ρgV = 1000 kg/m³ × 9.8 m/s² × 3785 m³ = 37,093,000 N
We now convert Newtons to pound-force.
1 N = 0.225 lb-f
So, F = 37,093,000 N = 37,093,000 N × 0.225 lb-f/1 N = 8,345,925 lb-f
So, the tower must be able to withstand 8,345,925 lb-f