Question

What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The specific heat capacity of silver is 0.235 J/(g C) Express your answer in ◦C.

Answer 1

Final temperature,
`T_f=21.85^(\circ)`

Step-by-step explanation:

Given that,

Mass of silver ring, m = 4 g

Initial temperature,
`T_i=41^(\circ)C`

Heat released, Q = -18 J (as heat is released)

Specific heat capacity of silver,
`c=0.235\ J/g\ C`

To find,

Final temperature

Solution,

The expression for the specific heat is given by :

`Q=mc\Delta T`

`Q=mc(T_f-T_i)`

`T_f=(-Q)/(mc)+T_i`

`T_f=(-18)/(4* 0.235)+41`

`T_f=21.85^(\circ)`

So, the final temperature of silver is 21.85 degrees Celsius.