209k views
2 votes
How would you describe the relationship between the real zeros and x-intercepts of the function y=log4(x-2)

User Ahrooran
by
8.1k points

2 Answers

5 votes

Answer:

Explanation:

First, look at y = log x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. A real zero occurs at x = 1, as log 1 = 0 => (1, 0). This point is also the x-intercept of y = log x.

Then look at y = log to the base 4 of x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. Again, a real zero occurs at x = 1, as log to the base 4 of 1 = 0 => (1, 0).

Finally, look at y=log to the base 4 of (x-2). The graph is the same as that of y = log to the base 4 of x, EXCEPT that the whole graph is translated 2 units to the right. Thus, the graph crosses the x-axis at (3, 0), which is also the x-intercept.

User Ardavan
by
8.3k points
5 votes

Answer:

When you set the function equal to zero, the solution is x = 3; therefore, the graph has an x-intercept at x = 3.

Explanation:

User Joseph Lin
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories