Question

A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble. What is the probability of choosing a green marble, not replacing it, and

then choosing a red marble?
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Answer 1

The probability for choosing green and red is 1/12

Explanation:

E2021

Answer 2

The probability for choosing green and red is
`(1)/(12)`

Solution:

Given that , A bag contains 1 red, 1 yellow, 1 blue, and 1 green marble.

We have to find what is the probability of choosing a green marble, not replacing it, and then choosing a red marble?

Now, we know that,

`\text { probability of an event }=\frac{\text { number of favourable outcomes }}{\text { total number of outcomes }}`

So, total possible outcomes = 1 red + 1 yellow + 1 blue + 1 green = 4

`\text { Now, probability for green marble }=\frac{1 \text { green marble }}{4 \text { marbles }}=(1)/(4)`

And now, total outcomes will be only 3 as we are not replacing the picked marble.

`\begin{array}{l}{\text { Then, probability for red marble }=\frac{1 \text { red marble }}{3 \text { marbles }}=(1)/(3)} \\\\ {\text { Then overall probability }=(1)/(4) * (1)/(3)=(1)/(12)}\end{array}`

Hence, the probability for choosing green and red is
`(1)/(12)`