Question

The resistance, R, to electricity of a cylindrical-shaped wire is given by the equation , where p represents the resistivity of the wire’s material, L represents the length of the wire, and d represents the diameter of the wire. What happens to the resistance of the wire as the diameter approaches 0?

Answer 1

d

Step-by-step explanation:

Answer 2

infinity

Step-by-step explanation:

Given that

Resistance = R

Resistivity = ρ

Length = L

Diameter = d

The resistance of wire R given as

`R=\rho(L)/(A)`

A=Area

`A=(\pi d^2)/(4)`

Now by putting the value of A

`R=\rho(L)/((\pi d^2)/(4))`

`R=\rho(4L)/(\pi d^2)`

When d tends to infinity then d² will also tends to infinity.

So when d tends to zero then the resistance tends to infinity.

Therefore answer is ---

infinity