Question

A balloon containing methane gas has a volume of 2.64 L at 31.0 C. What volume will the balloon occupy at 62.0 C?

Answer 1

The balloon will occupy the volume of 2.91 L at 62.0 °C .

Step-by-step explanation:

Using Charle's law

`\frac {V_1}{T_1}=\frac {V_2}{T_2}`

Given ,

V₁ = 2.64 L

V₂ = ?

T₁ = 31.0 °C

T₂ = 62.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (31.0 + 273.15) K = 304.15 K

T₂ = (62 + 273.15) K = 335.15 K

Using above equation as:

`(2.64)/(304.15)=(V_2)/(335.15)`

`V_2=(2.64\cdot \:335.15)/(304.15)`

New volume = 2.91 L

The balloon will occupy the volume of 2.91 L at 62.0 °C .