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The average distance between collisions for atoms in a real gas is known as the mean free path (see pp. 298-9 in McKay). Which of the answers below best represents the mean free path for gas molecules at STP with atomic radii on the order of 1.0 x 10-10 m? The average distance between collisions for atoms in a real gas is known as the mean free path (see pp. 298-9 in McKay). Which of the answers below best represents the mean free path for gas molecules at STP with atomic radii on the order of 1.0 x 10-10 m?

A. 30 nm
B. 3000 nm
C. 300 nm
D. 3 nm

1 Answer

0 votes

Answer:

300 nm

Step-by-step explanation:

R = Gas constant = 8.314 J/molK

r = Atomic radii =
1* 10^(-10)\ m

d = Atomic diameter =
2r=2* 10^(-10)\ m

At STP

T = Temperature = 273.15 K

P = Pressure = 100 kPa


N_A = Avogadro's number =
6.022* 10^(23)

The mean free path is given by


\lambda=(RT)/(\sqrt2d^2N_AP)\\\Rightarrow \lambda=(8.314* 273.15)/(\sqrt2 \pi * (2* 10^(-10))^2* 6.022* 10^(23)* 100000)\\\Rightarrow \lambda=2.12165* 10^(-7)\ m=212.165* 10^(-9)\ m=212.165\ nm

The answer that best represents the mean free path for gas molecules is 300 nm

User Jap Mul
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