Answer:
Part a)
![v = 26.3 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/lcv5u7a80mcqglckt0o0xdqckislyba1cv.png)
Part b)
![t = 5.53 s](https://img.qammunity.org/2020/formulas/physics/high-school/8n0ll2stto3cz0m17i2z4qk9y7eb00fsy9.png)
Step-by-step explanation:
As we know that there is no friction on the hill
so here by energy conservation we will have
![(1)/(2)mv^2 = mgL sin\theta](https://img.qammunity.org/2020/formulas/physics/high-school/gpxfei5feak2t04befll9zwx414lnkaf9w.png)
so we will have
![v^2 = 2gL sin\theta](https://img.qammunity.org/2020/formulas/physics/high-school/d70vq5sg5rcon7a8oiivykl0zagkv6ra88.png)
![v^2 = 2(9.81)(72.5) sin29](https://img.qammunity.org/2020/formulas/physics/high-school/lf7md3gokths9f26fbbl83t7r1wgilydq3.png)
![v^2 = 689.62](https://img.qammunity.org/2020/formulas/physics/high-school/vj7f3ni6r75yi529604l6l73zq98bm24a9.png)
![v = 26.3 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/lcv5u7a80mcqglckt0o0xdqckislyba1cv.png)
now in order to find the time we know that the acceleration along the surface is given as
![a = g sin29](https://img.qammunity.org/2020/formulas/physics/high-school/jmlldkw69s8srcd3bxc4w7lwqx5jif7ayu.png)
![a = 4.755 m/s^2](https://img.qammunity.org/2020/formulas/physics/high-school/m38w8n8ud5n49zt44s9fgy8v2iwjanll9f.png)
now we have
![v_f = v_i + at](https://img.qammunity.org/2020/formulas/physics/middle-school/1cset2hbhcdxo7q34bqods06bywswu8y3w.png)
![26.3 = 0 + 4.755 t](https://img.qammunity.org/2020/formulas/physics/high-school/m9oxszinqrrgb3o714a96abz7zesebj55y.png)
![t = 5.53 s](https://img.qammunity.org/2020/formulas/physics/high-school/8n0ll2stto3cz0m17i2z4qk9y7eb00fsy9.png)