Question

Consider this system of equations. Which shows the first equation written in slope-intercept form? 1/2(2y+10)=7x

A. y= 7x-10
B. y= 7/2x-5
C. y=7x-5
D. y=7/4x-5

Answer 1

C) y=7x-5

Explanation:

1/2(2y+10)=7x

y+5=7x

y=7x-5

Answer 2

Answer: C.
`y=7x-5`

Explanation:

The equation of a line in slope intercept form is given by :-

`y=mx+c`

The given equation is
`(1)/(2)(2y+10)=7x`

Multiplying 2 on both sides in the above equation , we get

`2y+10=14x`

Subtract 10 from both sides , we get

`2y=14x-10`

Divide both sides by 2 , we get

`y=7x-5`

Hence, the first equation written in slope-intercept form :
`y=7x-5`