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6 votes
6 votes
Solve for a in terms of b and c

b = 3a + 5ac​

User Marqueone
by
2.6k points

1 Answer

20 votes
20 votes
1 Factor out the common term
a
a.
b
=
a
(
3
+
5
c
)
b=a(3+5c)

2 Divide both sides by
a
a.
b
a
=
3
+
5
c
a
b

=3+5c

3 Subtract
3
3 from both sides.
b
a

3
=
5
c
a
b

−3=5c

4 Divide both sides by
5
5.
b
a

3
5
=
c
5
a
b

−3

=c

5 Simplify
b
a

3
5
5
a
b

−3

to
b
a
5

3
5
5
a
b




5
3

.
b
a
5

3
5
=
c
5
a
b




5
3

=c

6 Simplify
b
a
5
5
a
b



to
b
5
a
5a
b

.
b
5
a

3
5
=
c
5a
b


5
3

=c

7 Switch sides.
c
=
b
5
a

3
5
c=
5a
b


5
3


User Sydney
by
2.8k points