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On a coordinate plane, parallelogram K L M N shown. Point K is at (7, 7), point L is at (5, 3), point M is at (1, 1), and point N is at (3, 5). Which statement proves that parallelogram KLMN is a rhombus? a. The midpoint of both diagonals is (4, 4). b. The length of KM is
√(72) and the length of NL is
√(8). c. The slopes of LM and KN are both One-half and NK = ML =
√(20). d. The slope of KM is 1 and the slope of NL is –1.

User Metaphyze
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1 Answer

2 votes

Answer:

Option D.

Explanation:

Given information: KLMN is parallelogram, K(7,7), L(5,3), M(1,1) and N(3,5).

Diagonals of a parallelogram bisect each other.

If diagonals of a parallelogram are perpendicular to each other then the parallelogram is a rhombus.

If a line passes through two points
(x_1,y_1) and
(x_2,y_2), then the rate of change is


m=(y_2-y_1)/(x_2-x_1)

Slope of KM is


m_1=(1-7)/(1-7)=1

Slope of LN is


m_2=(5-3)/(3-5)=-1

The product of slopes of two perpendicular lines is -1.

Find the product of slopes.


m_1\cdot m_2=1\cdot (-1)=-1

The product of slopes of KM and NL is -1. It means diagonals are perpendicular and KLMN is a rhombus.

Therefore, the correct option is D.

User Jdeng
by
8.5k points
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