The proportions 1:2:1 are consistent with thenull hypothesis that the pink flowers are heterozygous for a single pair.
Option C
Explanation:
Chi square test is used to
(i) Find significant difference in two or more than two proportions
(ii) The goodness of fit between the observed and expected frequency.

![X^(2)=\left[((34-37.5)^(2))/(37.5)\right]+\left[((76-75)^(2))/(75)\right]+\left[((40-37.5)^(2))/(37.5)\right]](https://img.qammunity.org/2020/formulas/biology/high-school/oea1j1ugg3na208f69s3yp4pc8gojmshwi.png)
= 0.3266 + 0.0133 + 0.1666 = 0.506
5% Critical value = 5.991
Degree of freedom = 2