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Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74 J/g·°C. If 16.7 kJ of energy is absorbed by a 225-g sample of benzene at 20.0°C, what is its final temperature?

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Answer: The final temperature of the sample is 62.66°C

Step-by-step explanation:

To calculate the amount of heat absorbed, we use the equation:


Q=mc\Delta T

where,

Q = heat absorbed = 16.7 kJ = 16700 J (Conversion factor: 1 kJ = 1000 J)

m = Mass of the sample = 225 g

c = specific heat capacity of sample =
1.74J/g.^oC


\Delta T = change in temperature =
T_2-T_1=(T_2-20.0)

Putting values in above equation, we get:


16700=225g* 1.74J/g.^oC* (T_2-20)^oC\\\\T_2=62.66^oC

Hence, the final temperature of the sample is 62.66°C

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