Answer:
Force, |F| = 1360.24 N
Step-by-step explanation:
It is given that,
Water from a fire hose is directed horizontally against a wall at a rate of 69.4 kg/s,

Initial speed of the water, u = 19.6 m/s
Finally water comes to stop, v = 0
To find,
The magnitude of the force exerted on the wall.
Solution,
Let F is the force exerted on the wall. The product of mass and acceleration is called the force exerted. Using second law of motion to find it as :



|F| = 1360.24 N
So, the magnitude of the force exerted on the wall is 1360.24 N.