Question

Amaya ran around 3 times around a 1 mile track in 45 minutes, what was her average velocity for the trip?

Answer 1

Average Velocity = (displacement) / (time)

Displacement = distance and direction between the start-point and end-point, no matter what happens in between.

Amaya ran around the track, so she ended in the same place she started. The distance between her start-point and end-point was zero. So . . .

Average Velocity = zero.

= = = = = = = = = =

Average Speed = (distance covered) / (time to cover the distance)

Amaya's distance = (1 mile/track) x (3 tracks) = 3 miles

Time to cover the distance = (3/4 hour)

Average speed = (3 miles) / (3/4 hour)

Average speed = (3 ÷ 3/4) mi/hr

Average speed = (3 x 4/3) mi/hr

Average speed = 4 miles per hour

Answer 2

Since Amaya ran around a 1 mile track 3 times we can multiply this to find the total distance she traveled (displacement).

3 x 1 = 3 miles traveled.

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Formula:
`V_a_v_g~=~(displacement)/(change~in~time)`

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In this question the variables are classified as:

Displacement = 3 miles

Change in Time = 45 minutes

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Now, fill in the expression to solve.

`V_a_v_g~=~(45)/(3)\\V_a_v_g~=~15~`

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Amayas average velocity is 15 minutes per mile.

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Best Regards,

Wolfyy :)