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The number of calories consumed by customers at the Chinese buffet is normally distributed with mean 2689 and standard deviation 560. One randomly selected customer is observed to see how many calories X that customer consumes. Round all answers to 4 decimal places where possible. What is the distribution of X?

User Ccordon
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4 votes

Answer:
X\sim N(2689,\560)

Explanation:

Let X be a random variable that represents the number of calories consumed.

Given : The number of calories consumed by customers at the Chinese buffet is normally distributed with mean 2689 and standard deviation 560.

i.e. Population mean :
\mu=2689

Population standard deviation:
\sigma=560.

We can say X follows normal distribution
\mu=2689 and
\sigma=560

So , the distribution of X :
X\sim N(\mu,\ \sigma)

i.e.
X\sim N(2689,\560)

User Cansik
by
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