Question

The number of calories consumed by customers at the Chinese buffet is normally distributed with mean 2689 and standard deviation 560. One randomly selected customer is observed to see how many calories X that customer consumes. Round all answers to 4 decimal places where possible. What is the distribution of X?

Answer 1

Answer:
`X\sim N(2689,\560)`

Explanation:

Let X be a random variable that represents the number of calories consumed.

Given : The number of calories consumed by customers at the Chinese buffet is normally distributed with mean 2689 and standard deviation 560.

i.e. Population mean :
`\mu=2689`

Population standard deviation:
`\sigma=560`.

We can say X follows normal distribution
`\mu=2689` and
`\sigma=560`

So , the distribution of X :
`X\sim N(\mu,\ \sigma)`

i.e.
`X\sim N(2689,\560)`