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Expand y=(x+y)^2 and find x when y=2

1 Answer

4 votes

Explanation:


y = {x}^(2) + {y}^(2)


2 = {x}^(2) + {2}^(2)


2 = {x}^(2) + 4

Subtract 4 from both sides


- 2 = {x}^(2)

There's no solution for x when y = 2

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