63.7k views
0 votes
A 60 - kilogram person stands on a compression spring . The spring constant is 2500 Newtons per meter .

What is the displacement of the spring ?
A) 0.00392m
B)0.024m
C)0.1176 m
D) 0.2352m

1 Answer

7 votes

Answer:0.2352
m

Explanation:

Let the mass of the person be
m.

Let the spring constant be
k.

Let the displacement in spring be
x

Let the acceleration due to gravity be
g

As it is given that the person just stands,the forces are balanced.

So,
mg=kx

Given,


m=60Kg\\k=2500Nm^(-1)\\g=9.8ms^(-2)


60* 9.8=2500* x\\x=(588)/(2500)=0.2352m

User Marina Dunst
by
5.4k points