Question

A polynomial p has zeros when x =-2, x= 1/3, and x=3. What could be the equation of p

Answer 1

p(x)=(x+2)(x-3)(3x-1)

Explanation:

Answer 2

See attachment.

Explanation:

The roots of the polynomial are:

`x = - 2`

`x = (1)/(3)`

`x = 3`

The factors of this polynomial will therefore be:

`(x + 2)`

`(3x - 1)`

and

`(x - 3)`

The factored form is obtained as:

`f(x) = (x + 2)(3x - 1)(x - 3)`

The graph of this polynomial has intercepts at x =-2, x= 1/3, and x=3.