Answer:
1st mechanic charges $55 per hour
2nd mechanic charges $50 per hour
Explanation:
Suppose rate charged per hour for first meachnic is "x"
rate charged per hour for 2nd mechanic is "y"
So,
1st mechanic 10 hrs, 2nd mechanic 15 hrs, total charge 1300, so we can write:
10x + 15y = 1300
Also, total hourly rate of both is 105, so we can write:
x + y = 105
or
x = 105 - y
We can substitute this into 1st equation and solve for y:
![10x + 15y = 1300\\10(105-y) + 15y = 1300\\1050-10y+15y=1300\\5y=250\\y=50](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9ol5rwoboeax5fr61nk4lmyixseu65h6co.png)
And x is:
x = 105 - y
x = 105 - 50
x = 55
1st mechanic charges $55 per hour
2nd mechanic charges $50 per hour