Question

A stack of seven different cards are shuffled and spread out face down if three cards are turned face up how many different three card combinations are possible

Answer 1

Answer:35 ways

Explanation:

`^nC_(k)` is the number of ways of choosing
`k` distinct objects from a lot of
`n` distinct objects.

In the given question,

`n=7\\k=3\\`

`^nC_(k)=(n!)/((n-k)!k!)`

So,
`^7C_(3)=(7!)/(3!4!)=(210)/(6)=35`

So,there are
`35` ways in which three distinct cards can be selecte from seven distinct cards.