Answer:
c. 16 black rabbits, 0 white rabbits, 0 gray rabbits.
Step-by-step explanation:
Let dominant black allele be = B
Let recessive white allele be = b
True breeding rabbit would mean that they are homozygous in their genotype hence true breeding black rabbit will be BB and true breeding white rabbit will be bb.
BB X bb :
B B
b Bb Bb
b Bb Bb
All the offspring are heterozygous with one dominant B allele so the phenotype black colour will be produced and all 16 individuals of F1 generation will be black in colour.