Question

What is the standard form of y=-(x-2)(x-3)(x-2)?​

Answer 1

y=-x^3+7x^2-16x+12

Explanation:

y=-(x-2)(x-3)(x-2)

y=-(x^2-2x-3x+6)(x-2)

y=-(x^2-5x+6)(x-2)

y=-(x^3-5x^2+6x-2x^2+10x-12)

y=-(x^3-7x^2+16x-12)

y=-x^3+7x^2-16x+12