Register
What is the standard form of y=-(x-2)(x-3)(x-2)?​
118k views
5 votes
What is the standard form of y=-(x-2)(x-3)(x-2)?​

User Jirapong
by
4.9k points

1 Answer

1 vote

Answer:

y=-x^3+7x^2-16x+12

Explanation:

y=-(x-2)(x-3)(x-2)

y=-(x^2-2x-3x+6)(x-2)

y=-(x^2-5x+6)(x-2)

y=-(x^3-5x^2+6x-2x^2+10x-12)

y=-(x^3-7x^2+16x-12)

y=-x^3+7x^2-16x+12

User WojonsTech
by
5.8k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.6m questions

7.3m answers

Other Questions

What is the value of x? (-4) - x = 5
1/7 + 3/14 equivalent fractions
185g in the ratio 2:3
(3x1,000,000)+(3x100,000)+(2x100) what is this number written in standard form?
The function h = -t2 + 95 models the path of a ball thrown by a boy where h represents height, in feet, and t represents the time, in seconds, that the ball is in the air. Assuming the boy lives at sea
Link Copied!