Question

Find electric field at point p which is a distance l away from the both +q and -q

Answer 1

`\frac{1}{4*(pie)*\text{E}} *(q)/(I^(2) )+\frac{1}{4*(pie)*\text{E}} *(-q)/(I^(2) )`

Step-by-step explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

`=\frac{1}{4*(pie)*\text{E}} *(q)/(r^(2) )`

Where

• q is the charge
• r is the distance
• 
  `E` is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1
`=\frac{1}{4*(pie)*\text{E}} *(q)/(I^(2) )`

F2
`=\frac{1}{4*(pie)*\text{E}} *(-q)/(I^(2) )`

⇒

F1+F2=
`\frac{1}{4*(pie)*\text{E}} *(q)/(I^(2) )+\frac{1}{4*(pie)*\text{E}} *(-q)/(I^(2) )`