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If you were to use the quadratic formula to solve (identify the zeros) this equation, what would happen?

`y\ =\ x^{2}\ +\ 6x\ +\ 10`

User Calmar
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1 Answer

6 votes

Answer:

Explanation:

The best way to answer this is to graph it before using the quadratic formula. The graph is shown below.

Notice that the minimum doesn't come anywhere near the x axis. That means when you use the quadratic formula, you are going to get the square root of a negative number. Check out the discriminate.

√(b^2 - 4*a * c)

a = 1

b = 6

c = 10

√(36 - 4*1*10

√36 - 40

√-4

2*i

So there is no point going any further. You have no real roots.

If you were to use the quadratic formula to solve (identify the zeros) this equation-example-1
User Zouppen
by
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