Answer:
Recall the Entropy Balance (Second Law of Thermodynamics) equations for the system below
And for ideal gas, we know that
Change in Entropy of the air kJ/Kg.K, ΔS = S₁ - S ₂ = Cp Ln (T₂/T₁) - R Ln(P₂/P₁)
where R is gas constant =0.287kJ/kg.K and given
Cp=1.015 kJ/ kg.K
T₂ = 465k T₁=270k, P1=58kPa, P2=350kPa
substituting these values into the eqn above, we have
S = (1.015x 0.544) - (0.287x1.798)
S = 0.0363kJ/Kg.K
Hence, the mass specific entropy change associated with the compression process = 0.0363kJ/Kg.K