Question

A construction crew is building a straight ramp that rests on two beams. One beam is 3.5 feet tall and the other is 10.5 feet tall. The beams are 40 feet apart. What is the slope of the ramp?

Answer 1

Here is a picture of the answer if you don't want to read that guys longggg explanation

Explanation:

Answer 2

The slope of the ramp is
`(7)/(40)` if two beams are apart at 40 feet and at heights of 3.5 feet and 10.5 feet respectively.

Explanation:

The two beams are 40 feet apart this is the horizontal distance.

As per the given question 3.5 feet beam is at initial point that is
`x_(1)=0` and beams are apart 40 feet that is
`x_(2)=40`.

Vertical distance is the heights of the beam are
`\mathrm{y}_(1)=3.5` feet and other bean is
`\mathrm{y}_(2)=10.5`

To find the slope of the ramp we know that, slope is the ratio of the vertical change to the horizontal change.

`\text { slope of the ramp }=(y_(2)-y_(1))/(x_(2)-x_(1))`

Substitute the values
`x_(1)=0, x_(2)=40, y_(1)=3.5 \text { and } y_(2)=10.5` in the above formula.

`\text { slope of the ramp }=(10.5-3.5)/(40-0)`

`\text {slope of the ramp}=(7)/(40)`

Thus by using the slope formula we found that slope of the ramp for the given conditions is
`(7)/(40)`.