Question

a 15.00 mL sample of an unknown HClO4 solution requires titration with 25.64 mL of 0.2000 M NaOH to reach equivalence point. what is the concentration (molarity) of the unknown HClO4 solution

Answer 1

V₁ = 0.342 M

Step-by-step explanation:

Given data:

Volume of HClO₄ = 15.00 mL

Volume of NaOH = 25.64 mL

Molarity of NaOH = 0.2000 M

Molarity of HClO₄ = ?

Solution:

Formula:

M₁V₁ = M₂V₂

V₁ = M₂V₂ /M₁

V₁ = 0.2000 M ×25.64 mL /15.00 mL

V₁ = 5.128 M. mL /15.00 mL

V₁ = 0.342 M