Question

2. A man heats a balloon in the oven. If the balloon initially

has a volume of 0.9 liters and a temperature of 20°C,
what will the volume of the balloon be after he heats it to
a temperature of 230°C?

Answer 1

V₂ = 1.55 L

Step-by-step explanation:

Given data:

Initial volume = 0.9 L

Initial temperature = 20°C

Final volume = ?

Final temperature = 230°C

Solution:

20°C = 20+273 = 293 k

230°C = 230+273 = 503 K

According to Charles law,

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 0.9 L . 503 K/ 293 k

V₂ = 452.7 L.K /293 k

V₂ = 1.55 L