Question

a skydiver jumps out of a airplane traveling with a horizontal velocity of 394.3m/s she falls for 3.9 seconds before she opens her parachute how far has she traveled in the horizontal direction in this time​

Answer 1

Step-by-step explanation:

Assume no air resistance before she opens her parachute.

Given in the x direction:

v₀ = 394.3 m/s

a = 0 m/s²

t = 3.9 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (394.3 m/s) (3.9 s) + ½ (0 m/s²) (3.9 s)²

Δx ≈ 1538 m

Round as needed.