231k views
2 votes
(1 point) A new computer virus attacks a folder consisting of 200 files. Each file gets damaged with probability 0.2 independently of other files. What is the probability that fewer than 50 files will get damaged?

User AfamO
by
5.9k points

1 Answer

6 votes

Answer:

0.9655

Explanation:

Given that a new computer virus attacks a folder consisting of 200 files

Probability for each file gets damaged = p = probability for success in each trial =
0.2

Each file is independent of the other.

Hence X no of files damaged is binomial with n =200 and p = 0.20

Here n denotes the number of files and p probability for success in each trial

We have
q=1-0.2 =0.8

Required probability
=P(X\leq 50)\\=\Sigma _0^(50) 50Cr (0.2)^r (0.8)^(200-r)

=0.9655

User Jeiea
by
5.9k points