Answer:
0.9655
Explanation:
Given that a new computer virus attacks a folder consisting of 200 files
Probability for each file gets damaged = p = probability for success in each trial =
![0.2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jok3ohr4xx7oqg0pixt6v2dbricg8nt2s8.png)
Each file is independent of the other.
Hence X no of files damaged is binomial with n =200 and p = 0.20
Here n denotes the number of files and p probability for success in each trial
We have
![q=1-0.2 =0.8](https://img.qammunity.org/2020/formulas/mathematics/college/jjd68z6cndo70h36b2bf7cltho0mq67ol1.png)
Required probability
![=P(X\leq 50)\\=\Sigma _0^(50) 50Cr (0.2)^r (0.8)^(200-r)](https://img.qammunity.org/2020/formulas/mathematics/college/qh9ky21r9rhuu7x30g26ncf39dl9rt40o7.png)
=0.9655