Answer
given,
mass of bowling ball = 7.25 Kg
moving speed of the bowling ball = 9.85 m/s
mass of bowling in = 0.875 Kg
scattered at an angle = θ = 21.5°
speed after the collision = 10.5 m/s
angle of the bowling ball
![tan \theta_1 = (-[m_2v_2Sin \theta_2])/(m_1v_1 - (m_2v_2cos \theta_2))](https://img.qammunity.org/2020/formulas/physics/college/ed7a7qxryifhfle1d108ovwuxagjaclpgq.png)
![tan \theta_1 = (-[0.875* 10.5 * Sin 21.5^0])/(7.25* 9.85 - (0.875* 10.5 * cos 21.5^0))](https://img.qammunity.org/2020/formulas/physics/college/6lrktwinknp74wukvkbyax7giy5d3of31p.png)
![tan \theta_1 = (-[3.3672])/(62.86)](https://img.qammunity.org/2020/formulas/physics/college/uonyxbogwizbfr63yb12y2k8wvnz0lv26v.png)


b) magnitude of final velocity


v = 8.68 m/s