Question

You want the current amplitude through a inductor with an inductance of 4.30 mH (part of the circuitry for a radio receiver) to be 3.00 mA when a sinusoidal voltage with an amplitude of 12.0 V is applied across the inductor.A) What frequency is required?f = ____________Hz.

Answer 1

`f=1480.52 Hz`

Step-by-step explanation:

For the circuit of the radio knowing the voltage in a inductor is VL and the relation of element is:

`V_L=I*Z_L*w`

Where
`I= 300mA`,
`Z_L=4.3mH`,
`V_L= 12V` and
`w=2\pi *f`

Knowing that the frequency influence in the performance of the inductor so:

`V_L=I*Z_L*2\pi *f`

Solve to f'

`f=(V_L)/(I*Z_L*2\pi ) =(12v)/(300mA*43.mH*2\pi)`

`f=1480.52 Hz`