Question

Consider the following balanced reaction. What mass (in g) of CO2 can be formed from 288 mg of O2? Assume that there is excess C3H7SH present.C3H7SH(l) + 6 O2(g) → 3 CO2(g) + SO2(g) + 4 H2O(g)

Answer 1

0.198 g is the mass, we can obtained from 288 mg CO2.

Step-by-step explanation:

C3H7SH(l) + 6 O2(g) → 3 CO2(g) + SO2(g) + 4 H2O(g)

If we assume the C3H7SH in excess, the limiting reactant is the O2 so, now we can work.

Molar mass O2 = 32 g/m

288 mg = 0.288 g

Mass / Molar mass = Moles

0.288 g / 32 g/m = 9x10⁻³ moles

So, 6 moles of O2 are needed to make 3 moles of CO2,

how many moles of CO2, can we make, from 9x10⁻³ moles of O2.

6 moles O2 _____ 3 moles CO2

9x10⁻³ moles O2 ____ (9x10⁻³ . 3 ) /6 = 4.5x10⁻³ moles of CO2

Molar mass CO2 = 44 g/m

Molar mass . moles = mass

44 g/m . 4.5x10⁻³ moles = 0.198 g

Answer 2

0.198g

Step-by-step explanation:

From the reaction equation, we can see that 6 moles of O2 yielded 3 moles of CO2. Let's keep this.

Now we need to know the number of moles of oxygen gas reacted.

As we know, 1000 milligrams = 1 gram. Hence, 288mg will be equal to 288/1000g = 0.288g.

To calculate the number of moles of oxygen gas reacted, we simply divide the mass of oxygen reacted by the molar mass of the oxygen reacted.

This is obtained from the relation:

Mass of oxygen reacted = number of moles of oxygen reacted × molar mass of oxygen molecule.

Hence, the number of moles of oxygen reacted = mass of oxygen reacted ÷ molar mass of oxygen molecule

To get the molar mass of the oxygen molecule, we simply multiply the relative atomic mass of oxygen by 2. The relative atomic mass if oxygen is 16. Hence, the molar mass would be 16 ×2 = 32g/mol.

The number of moles = 0.288 ÷ 31 = 0.009moles

Now from the relation at first, 6 moles O2 yielded 3 moles CO2.

hence, 0.009moles oxygen will yield (0.009 × 3) ÷ 6 = 0.0045 moles CO2.

Now to calculate the mass of CO2 yielded, we use the relation:

Mass of CO2 yielded = number of moles of CO2 yielded × molar mass of CO2.

The molar mass of CO2 = 12 + 2(16) = 12 + 32 = 44g/mol.

The mass thus yielded = 44 × 0.0045 = 0.198g